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JEE Main 2019 Chemistry question

ChemistryStructure of AtomJEE Main 2019

The quantum numbers of four electrons are given below: I. n = 4, l = 2, = −2, II. n = 3, l = 2, = 1, III. n = 4, l = 1, = 0, IV. n = 3, l = 1, = 1, The correct order of their increasing energies will be:

Answer: (B)

Solution

(n + l): I = 6, II = 5 (n = 3), III = 5 (n = 4), IV = 4 ⇒ IV < II < III < I.

Question ID VK-009245