JEE Main 2019 Mathematics question
All possible numbers are formed using the digits 1, 1, 2, 2, 2, 2, 3, 4, 4 taken all at a time. The number of such numbers in which the odd digits occupy even places is:
Answer: (A)
Solution
Odd digits 1, 1, 3 in 3 of the 4 even places: 4C_3\dfrac{3!}{2!}$
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