JEE Main 2019 Physics question
A parallel plate capacitor has 1 μF capacitance. One of its two plates is given +2 μC charge and the other plate, +4 μC charge. The potential difference developed across the capacitor is:
Answer: (A)
Solution
Inner faces carry ±(4 − 2)/2 = ±1 μC; V = 1 μC/1 μF = 1 V.