JEE Main 2019 Physics question

PhysicsElectrostatic Potential and CapacitanceJEE Main 2019

A parallel plate capacitor has 1 μF capacitance. One of its two plates is given +2 μC charge and the other plate, +4 μC charge. The potential difference developed across the capacitor is:

Answer: (A)

Solution

Inner faces carry ±(4 − 2)/2 = ±1 μC; V = 1 μC/1 μF = 1 V.

Question ID VK-009309