JEE Main 2019 Physics question

The electric field of light wave is given as . This light falls on a metal plate of work function 2 eV. The stopping potential of the photo-electrons is: Given, E (in eV) = .

• (A)0.72 V
• (B)2.0 V
• (C)0.48 VCorrect
• (D)2.48 V