JEE Main 2019 Physics question

PhysicsWavesJEE Main 2019

A string is clamped at both the ends and it is vibrating in its 4th harmonic. The equation of the stationary wave is Y = 0.3 sin(0.157x) cos(200πt). The length of the string is: (All quantities are in SI units.)

Answer: (B)

Solution

k = 0.157 = π/20 ⇒ λ = 40 m; 4th harmonic: L = 4λ/2 = 80 m.

Question ID VK-009417