JEE Main 2019 Chemistry question
The pH of a 0.02 M NHCl solution will be [given (NHOH) = and log 2 = 0.301]
Answer: (B)
Solution
pH = 7 − ½pK − ½log C = 7 − 2.5 + 0.85 = 5.35.
The pH of a 0.02 M NHCl solution will be [given (NHOH) = and log 2 = 0.301]
pH = 7 − ½pK − ½log C = 7 − 2.5 + 0.85 = 5.35.