JEE Main 2019 Mathematics question
The tangent and normal to the ellipse at the point P(2, 2) meet the x-axis at Q and R, respectively. Then the area (in sq. units) of the triangle PQR is:
Answer: (C)
Solution
Slope of tangent −3/5: Q(16/3, 0); normal slope 5/3: R(4/5, 0); area = ½ · (68/15) · 2 = 68/15.