JEE Main 2018 Physics question

PhysicsElectromagnetic InductionJEE Main 2018

An ideal capacitor of capacitance 0.2 µF is charged to a potential difference of 10V. The charging battery is then disconnected. The capacitor is then connected to an ideal inductor of self inductance 0.5 mH. The current at a time when the potential difference across the capacitor is 5V, is:

Answer: (A)

Solution

Question ID VK-009571