JEE Main 2018 Chemistry question
at 500 K for substance 'S' in liquid state and gaseous state are + 100.7 kcal mol and + 103 kcal mol, respectively. Vapour pressure of liquid 'S' at 500 K is approximately equal to - (R = 2cal K mol)
Answer: (D)
Solution
kcal \ln\ln$ p =
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