JEE Main 2019 Physics question
Moment of inertia of a body about a given axis is 1.5 kg m. Initially the body is at rest. In order to produce a rotational kinetic energy of 1200 J, the angular acceleration of 20 rad/s must be applied about the axis for a duration of:
Answer: (D)
Solution
rad/s; t = 40/20 = 2 s.