The position vector of a particle changes with time according to the relation r(t) = 15t^2 i + (4 - 20t^2) j....

Question

The position vector of a particle changes with time according to the relation r(t) = 15t^2 i + (4 - 20t^2) j. What is the magnitude of the acceleration at t = 1?

Accepted Answer

(C)

JEE Main 2019 Physics question

Solution