JEE Main 2019 Chemistry question

At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be: (molar mass of urea = 60 g mol)

• (A)0.031 mmHg
• (B)0.017 mmHgCorrect
• (C)0.028 mmHg
• (D)0.027 mmHg