JEE Main 2019 Mathematics question

Mathematics Sequence and Series JEE Main 2019

The sum up to 10th term is:

(A)660Correct
(B)680
(C)600
(D)620

Answer: (A)

Solution

nth term \dfrac{(2n+1)[\frac{n(n+1)}{2}]^2}\frac${n(n+1)(2

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Question ID VK-009913