JEE Main 2019 Physics question
A series AC circuit containing an inductor (20 mH), a capacitor (120 μF) and a resistor (60 Ω) is driven by an AC source of 24 V/50 Hz. The energy dissipated in the circuit in 60 s is:
Answer: (C)
Solution
Ω, Ω, Z ≈ 63.3 Ω; A; energy = J.