JEE Main 2019 Mathematics question
Let f: [0, 1] → R be such that f(xy) = f(x)·f(y), for all x, y ∈ [0, 1], and f(0) ≠ 0. If y = y(x) satisfies the differential equation, with y(0) = 1, then is equal to:
Answer: (B)
Solution
f(0) = f(0)f(y) ⇒ f ≡ 1 ⇒ y = x + 1 ⇒ 5/4 + 7/4 = 3.