JEE Main 2019 Mathematics question
Let the equations of two sides of a triangle be 3x − 2y + 6 = 0 and 4x + 5y − 20 = 0. If the orthocentre of this triangle is at (1, 1), then the equation of its third side is:
Answer: (A)
Solution
Vertex A = (10/23, 84/23); third side ⊥ AH, direction of normal (13, −61);
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