JEE Main 2019 Physics question
A convex lens is put 10 cm from a light source and it makes a sharp image on a screen, kept 10 cm from the lens. Now a glass block (refractive index 1.5) of 1.5 cm thickness is placed in contact with the light source. To get the sharp image again, the screen is shifted by a distance d. Then d is:
Answer: (C)
Solution
f = 5 cm; the block shifts the object by 1.5(1 − 1/1.5) = 0.5 cm
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