JEE Main 2019 Mathematics question
Let be a function defined as . Then, f is:
Answer: (D)
Solution
x = 5 gives b = 5, x = 1 gives a = 0, but then at x = 3: a + 3b = 15 ≠ b + 15 = 20.
Let be a function defined as . Then, f is:
x = 5 gives b = 5, x = 1 gives a = 0, but then at x = 3: a + 3b = 15 ≠ b + 15 = 20.