JEE Main 2019 Physics question
The trajectory of a projectile near the surface of the earth is given as . If it were launched at an angle with speed then (g = 10 ms):
Answer: (A)
Solution
tan θ = 2 ⇒ cos θ = 1/√5; ⇒ m/s.
The trajectory of a projectile near the surface of the earth is given as . If it were launched at an angle with speed then (g = 10 ms):
tan θ = 2 ⇒ cos θ = 1/√5; ⇒ m/s.