JEE Main 2019 Chemistry question
The mole fraction of a solvent in aqueous solution of a solute is 0.8. The molality (in mol kg) of the aqueous solution is:
Answer: (C)
Solution
0.2 mol solute per 0.8 mol (14.4 g) water ⇒ m = 0.2/0.0144 = 13.88.
The mole fraction of a solvent in aqueous solution of a solute is 0.8. The molality (in mol kg) of the aqueous solution is:
0.2 mol solute per 0.8 mol (14.4 g) water ⇒ m = 0.2/0.0144 = 13.88.