JEE Main 2019 Chemistry question
Enthalpy of sublimation of iodine is 24 cal g at 200 °C. If specific heat of I(s) and I(vap) are 0.055 and 0.031 cal gK respectively, then enthalpy of sublimation of iodine at 250°C in cal g is:
Answer: (B)
Solution
Kirchhoff: 24 + (0.031 − 0.055)(50) = 22.8.