JEE Main 2019 Chemistry question
An ideal gas is allowed to expand from 1 L to 10 L against a constant external pressure of 1 bar. The work done in kJ is:
Answer: (D)
Solution
w = −1 bar × 9 L = −9 L bar = −0.9 kJ.
An ideal gas is allowed to expand from 1 L to 10 L against a constant external pressure of 1 bar. The work done in kJ is:
w = −1 bar × 9 L = −9 L bar = −0.9 kJ.