JEE Main 2019 Mathematics question
Consider the differential equation, . If value of y is 1 when x = 1, then the value of x for which y = 2, is:
Answer: (A)
Solution
with C = −1/e ⇒ at y = 2: x = 3/2 − 1/√e.
Consider the differential equation, . If value of y is 1 when x = 1, then the value of x for which y = 2, is:
with C = −1/e ⇒ at y = 2: x = 3/2 − 1/√e.