JEE Main 2019 Physics question
In a radioactive decay chain, the initial nucleus is Th. At the end there are 6 α-particles and 4 β-particles which are emitted. If the end nucleus is X, A and Z are given by:
Answer: (B)
Solution
A = 232 − 24 = 208; Z = 90 − 12 + 4 = 82.