JEE Main 2019 Mathematics question

MathematicsIndefinite IntegrationJEE Main 2019

The integral \displaystyle\int_1^e\left\{\left(\frac xe\right)^{2x} - \left(\frac ex\right)^x\right\}\log_ex\,dx is equal to:

Answer: (B)

Solution

and $(Missing argument for \dfrac\dfrac =

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Question ID VK-010265