JEE Main 2019 Chemistry question
Freezing point of a 4% aqueous solution of X is equal to freezing point of 12% aqueous solution of Y. If molecular weight of X is A, then molecular weight of Y is:
Answer: (C)
Solution
Equal molality: 4/A = 12/M.
Freezing point of a 4% aqueous solution of X is equal to freezing point of 12% aqueous solution of Y. If molecular weight of X is A, then molecular weight of Y is:
Equal molality: 4/A = 12/M.