JEE Main 2019 Chemistry question
In a chemical reaction, A + 2B ⇌ 2C + D, the initial concentration of B was 1.5 times of the concentration of A, but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant (K) for the aforesaid chemical reaction is:
Answer: (D)
Solution
a − x = 1.5a − 2x ⇒ x = a/2; K = .