Let C_1 and C_2 be the centres of the circles x^2 + y^2 - 2x - 2y - 2 = 0 and x^2 + y^2 - 6x - 6y + 14 = 0...

Question

Let C_1 and C_2 be the centres of the circles x^2 + y^2 - 2x - 2y - 2 = 0 and x^2 + y^2 - 6x - 6y + 14 = 0 respectively. If P and Q are the points of intersection of these circles, then the area (in sq. units) of the quadrilateral PC_1QC_2 is:

Accepted Answer

(A)

JEE Main 2019 Mathematics question

Solution