Test SeriesFree PYQsExamsPricing

JEE Main 2019 Physics question

PhysicsThermal Properties of MatterJEE Main 2019

When 100 g of a liquid A at 100°C is added to 50 g of a liquid B at temperature 75°C, the temperature of the mixture becomes 90°C. The temperature of the mixture, if 100 g of liquid A at 100°C is added to 50 g of liquid B at 50°C, will be:

Answer: (D)

Solution

100(10) = 50(15) ⇒ ; then 75(100 − T) = 50(T − 50) ⇒ T = 80°C.

Question ID VK-010384