JEE Main 2019 Physics question
The mass and the diameter of a planet are three times the respective values for the Earth. The period of oscillation of simple pendulum on the Earth is 2 s. The period of oscillation of the same pendulum on the planet would be:
Answer: (D)
Solution
g′ = g(3/9) = g/3 ⇒ T′ = 2√3 s.