JEE Main 2019 Physics question

PhysicsElectromagnetic WavesJEE Main 2019

A 27 mW laser beam has a cross-sectional area of 10 mm. The magnitude of the maximum electric field in this electromagnetic wave is given by: [Given permittivity of space = SI units, Speed of light c = m/s]

Answer: (C)

Solution

I = 2700 W/m; kV/m.

Question ID VK-010398