JEE Main 2019 Physics question
A particle of mass m and charge q is in an electric and magnetic field given by ; . The charged particle is shifted from the origin to the point P(x = 1; y = 1) along a straight path. The magnitude of the total work done is:
Answer: (D)
Solution
The magnetic force does no work; W = q = q(2 + 3) = 5q.