JEE Main 2019 Physics question

PhysicsUnits and MeasurementJEE Main 2019

If speed (V), acceleration (A) and force (F) are considered as fundamental units, the dimension of Young's modulus will be:

Answer: (C)

Solution

L = V/A, T = V/A, M = F/A ⇒ Y = MLT = FAV.

Question ID VK-010404