JEE Main 2019 Chemistry question
The coordination number of Th in K[Th(CO)(OH)] is: (CO = Oxalato)
Answer: (B)
Solution
4 × 2 (bidentate oxalate) + 2 = 10.
The coordination number of Th in K[Th(CO)(OH)] is: (CO = Oxalato)
4 × 2 (bidentate oxalate) + 2 = 10.