JEE Main 2019 Physics question
A body is projected at t = 0 with a velocity 10 ms at an angle of 60° with the horizontal. The radius of curvature of its trajectory at t = 1 s is R. Neglecting air resistance and taking acceleration due to gravity g = 10 ms, the value of R is:
Answer: (A)
Solution
At t = 1 s: = 5, = −1.34, v ≈ 26.8; ⇒ R = v/ ≈ 2.8 m.