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JEE Main 2019 Physics question

PhysicsWavesJEE Main 2019

Equation of travelling wave on a stretched string of linear density 5 g/m is y = 0.03 sin(450t − 9x) where distance and time are measured in SI units. The tension in the string is:

Answer: (D)

Solution

v = 450/9 = 50 m/s; T = μv = 0.005 × 2500 = 12.5 N.

Question ID VK-010494