JEE Main 2019 Mathematics question
Let and g(x) = |f(x)| + f(|x|). Then, in the interval (−2, 2), g is:
Answer: (D)
Solution
g = x on (−2, 0), 0 on [0, 1], 2(x − 1) on (1, 2): a corner only at x = 1.
Let and g(x) = |f(x)| + f(|x|). Then, in the interval (−2, 2), g is:
g = x on (−2, 0), 0 on [0, 1], 2(x − 1) on (1, 2): a corner only at x = 1.