JEE Main 2019 Mathematics question
Equation of a common tangent to the parabola and the hyperbola xy = 2 is:
Answer: (D)
Solution
y = mx + 1/m touches xy = 2 when ⇒ m = −1/2.
Equation of a common tangent to the parabola and the hyperbola xy = 2 is:
y = mx + 1/m touches xy = 2 when ⇒ m = −1/2.