JEE Main 2019 Mathematics question
Let [x] denote the greatest integer less than or equal to x. Then
Answer: (C)
Solution
Right limit: π + 1 (sin(0) = 0 for [x] = 0); left limit: [x] = −1 gives , so π. The limits differ.
Let [x] denote the greatest integer less than or equal to x. Then
Right limit: π + 1 (sin(0) = 0 for [x] = 0); left limit: [x] = −1 gives , so π. The limits differ.