JEE Main 2019 Mathematics question

Mathematics Methods of Differentiations JEE Main 2019

If (y > 0), then at x = e is equal to:

(A)
(B)
(C)Correct
(D)

Answer: (C)

Solution

At x = e: 0 + 1 − 2e + 2yy′ = 0 and .

Question ID VK-010550