JEE Main 2019 Physics question
A particle executes simple harmonic motion with an amplitude of 5 cm. When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then, its periodic time in seconds is:
Answer: (D)
Solution
⇒ ω = 3/4 ⇒ T = 8π/3.