JEE Main 2019 Physics question

PhysicsElectrostatic Potential and CapacitanceJEE Main 2019

A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates. The work done by the capacitor on the slab is:

Answer: (A)

Solution

pJ.

Question ID VK-010587