JEE Main 2019 Chemistry question

Chemistry Chemical Bonding and Molecular Structure JEE Main 2019

The type of hybridisation and number of lone pair(s) of electrons of Xe in XeOF, respectively, are:

(A)spd and 2
(B)spd and 2
(C)spd and 1
(D)spd and 1Correct

Answer: (D)

Solution

5 σ bonds + 1 lone pair ⇒ spd (square pyramidal).

Question ID VK-010678