JEE Main 2019 Chemistry question
The total number of isomers for a square planar complex [M(F)(Cl)(SCN)(NO)] is:
Answer: (C)
Solution
3 geometrical isomers × 4 linkage combinations (SCN/NCS, NO/ONO) = 12.
The total number of isomers for a square planar complex [M(F)(Cl)(SCN)(NO)] is:
3 geometrical isomers × 4 linkage combinations (SCN/NCS, NO/ONO) = 12.