JEE Main 2019 Mathematics question

MathematicsContinuity and DifferentiabilityJEE Main 2019

Let be a function such that , x ∈ R. Then f(2) equals:

Answer: (B)

Solution

f‴ = 6; with a = f′(1), b = f″(2): a = 3 + 2a + b, b = 12 + 2a ⇒ a = −5, b = 2; f(2) = 8 − 20 + 4 + 6 = −2.

Question ID VK-010719