JEE Main 2019 Chemistry question
25 g of an unknown hydrocarbon upon burning produces 88 g of CO and 9 g of HO. This unknown hydrocarbon contains:
Answer: (D)
Solution
C = 88 × 12/44 = 24 g; H = 9 × 2/18 = 1 g.
25 g of an unknown hydrocarbon upon burning produces 88 g of CO and 9 g of HO. This unknown hydrocarbon contains:
C = 88 × 12/44 = 24 g; H = 9 × 2/18 = 1 g.