JEE Main 2019 Chemistry question
A solution is prepared by dissolving 0.6 g of urea (molar mass = 60 g mol) and 1.8 g of glucose (molar mass = 180 g mol) in 100 mL of water at 27ºC. The osmotic pressure of the solution is: (R = 0.08206 L atm K mol)
Answer: (C)
Solution
0.02 mol in 0.1 L: π = 0.2 × 0.08206 × 300.