JEE Main 2019 Mathematics question
Not in JEE Main syllabus
A value of , for which , is:
Answer: (B)
Solution
The determinant equals 2 + 4 cos 6θ ⇒ cos 6θ = −1/2 ⇒ θ = π/9. (The first row is cut in the source; the official matrix is used.)
Not in JEE Main syllabus
A value of , for which , is:
The determinant equals 2 + 4 cos 6θ ⇒ cos 6θ = −1/2 ⇒ θ = π/9. (The first row is cut in the source; the official matrix is used.)