JEE Main 2020 Physics question

PhysicsLaws of MotionJEE Main 2020

A mass of 10 kg is suspended by a rope of length 4m, from the ceiling, A force F is applied horizontally at the mid-point of the rope such that the top half of the rope makes an angle of 45° with the vertical. Then F equals : (Take g = 10 and the rope to be massless) -

Answer: (B)

Solution

Question ID VK-010846