JEE Main 2020 Chemistry question
3 g of acetic acid is added to 250 mL of 0.1 M HCl and the solution made up to 500 mL. To 20 mL of this solution mL of 5 M NaOH is added. The pH of the solution is . [Given : pKa of acetic acid = 4.75, molar mass of acetic acid = 60 g/mol, log3 = 0.4771] Neglect any changes in volume.
Answer: 5.23
Solution
In 20 mL: acetic acid 2 mmol, HCl 1 mmol, NaOH 2.5 mmol. HCl is neutralised first, leaving 1.5 mmol NaOH which converts 1.5 mmol
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